Decomposition
Beginning of paper
Purpose: In this lab we will observe the products of of potassium
perchlorate (KClO4). We will then predict from our results the correct chemical
reaction equation.
Procedure: 1. Weigh out about 4.0g of KClO4 in a test tube. Record the
accurate weight below. Product Weight Before Weight After M ....
Middle of paper
.... the test tube into the bottle of water, forcing
the water out. Burning ember re-ignited when placed into the bottle of O2.
Calculations: 1. The number of moles of KClO4 that we began with is .03 moles.
4.0g ¸ 138.6g/mol = .03 moles 2. The number of moles of O2 that were present in
our sample of KClO4 was .06 moles. 1.9g ¸ 32g/mole = .06 moles 3. The number of
moles of O2 lost is .02 moles. 1.7g ¸ 32g/mol = .05 moles 4. KClO4 à KCl + 202
4.0g ¸ 138.6g/mol = .03 moles ´ 202 ¸ KClO4 = ....
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Word count: 253
Page count: 1 (approximately 250 words per page)
